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OpenDialog control question
Posted: 22 Mar 06 10:46 AM
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buy naltrexone online usa buy naltrexone without prescription go fiogf49gjkf0d Has anyone successfully used the OpenDialog control? Whenever I get the .FileName property I get some random gibberish instead of the file name. Is there something special that needs to be done to get this information? I'm using 6.2.3. I've got the OpenDialog control on the form and I have a button that calls the OpenDialog.execute method to show the dialog screen. Then I get the FileName property on a close event. It seems that it should be that simple, but is there more that needs to be done?
Code snippet below:
Sub cmdOpenFileClick(Sender)
odFile.FileName = empty
odfile.Execute
End Sub
Sub OpenDialog1Close(Sender)
msgbox sender.FileName
End Sub
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Re: OpenDialog control question
Posted: 23 Mar 06 7:25 AM
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fluoxetine capsules 20mg fluoxetine 20mg tablets
- opnFile is the OpenDialog control
- txtFile is an Edit control showing the default or selected filename
- cmdChange is a button control clicked to popup the Open Dialog and select or enter a different filename
- cmdOK is a button control clicked to create a temp text file. If successful it gets copied to the selected file.
sub AXForm_Change(Sender)
...
'set default output file for 4th Shift transfer
opnFile.DefaultExt = "txt"
txtFile.Text = "DefaultOrderTransferFileName"
opnFile.FileName = txtFile.Text
opnFile.Filter = "Text Files (*.txt)|*.txt"
...
end sub
sub cmdChange_OnClick(Sender)
opnFile.Execute
txtFile.Text = opnFile.FileName
end sub
sub cmdOK_Click(Sender)
...
'verify can open transfer output file
set fso = CreateObject("Scripting.FileSystemObject")
set objOutFile = fso.OpenTextFile(opnFile.FileName, cForAppending, True)
if not fso.FileExists(opnFile.FileName) then
ErrorMsg("Could not open transfer output file: " & opnFile.FileName)
CloseRS 2, objOutFile, fso
exit sub
end if
objOutFile.Close 'close for now, will reopen when ready to update
...
end sub
sub CopyOrderFile
objWrkFile.Close 'close the work file to end writing mode
set objWrkFile = fso.OpenTextFile(strWrkFile, cForReading, True)
if not fso.FileExists(strWrkFile) then
ErrorMsg("Could not open transfer work file for copy: " & strWrkFile)
exit sub
end if
'open transfer file
set objOutFile = fso.OpenTextFile(opnFile.FileName, cForAppending, True)
if not fso.FileExists(opnFile.FileName) then
ErrorMsg("Could not open transfer file for copy: " & opnFile.FileName)
exit sub
end if
'copy work file to transfer file
while not objWrkFile.AtEndOfStream
objOutFile.WriteLine(objWrkFile.ReadLine)
wend
objOutFile.Close
end sub
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Re: OpenDialog control question
Posted: 23 Mar 06 12:21 PM
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fiogf49gjkf0d Thanks for the help. I was able to get it to work by putting the FileName property reference in the button click event. Looks like the FileName property is filled after the the Execute method completes and not available during the Onclose event. |
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